-y^2-4y+4.43=0

Solution for -y^2-4y+4.43=0 equation:

-y^2-4y+4.43=0

We add all the numbers together, and all the variables

-1y^2-4y+4.43=0

a = -1; b = -4; c = +4.43;
Δ = b2-4ac
Δ = -42-4·(-1)·4.43
Δ = 33.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{33.72}}{2*-1}=\frac{4-\sqrt{33.72}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{33.72}}{2*-1}=\frac{4+\sqrt{33.72}}{-2}
$